Jump to content

1975 South American Open

From Wikipedia, the free encyclopedia
(Redirected from1975 ATP Buenos Aires)
1975 South American Open
Date10–16 November
Edition8th
CategoryGrand Prix(Grade A)
Draw32S / 32D
Prize money$50,000
SurfaceClay/ outdoor
LocationBuenos Aires,Argentina
Champions
Singles
ArgentinaGuillermo Vilas[1]
Doubles
ItalyPaolo Bertolucci/ItalyAdriano Panatta[2]
1974· South American Open ·1976

The1975 South American Openalso valid as theATP Buenos Aireswas a men'sGrand Prix tennis circuittournament played on outdoorclay courtsinBuenos Aires,Argentina. The event was part of the1975 Grand Prix circuitand was held from 10 November through 16 November 1975. First-seededGuillermo Vilaswon the singles title.[3]

Finals

[edit]

Singles

[edit]

ArgentinaGuillermo VilasdefeatedItalyAdriano Panatta6–1, 6–4, 6–4

  • It was Vilas' 8th title of the year and the 20th of his career.

Doubles

[edit]

ItalyPaolo Bertolucci/ItalyAdriano PanattadefeatedWest GermanyJürgen Fassbender/West GermanyHans-Jürgen Pohmann3–6, 6–1, 8–6

  • It was Bertolucci's 5th title of the year and the 8th of his career. It was Panatta's 6th title of the year and the 11th of his career.

References

[edit]
  1. ^"1975 Buenos Aires – Singles draw".Association of Tennis Professionals (ATP).
  2. ^"1975 Buenos Aires – Doubles draw".Association of Tennis Professionals (ATP).
  3. ^John Barrett,ed. (1976).World of Tennis '76: a BP and Commercial Union yearbook.London: Queen Anne Press. pp. 122, 123.ISBN9780362002768.OCLC650229036.
[edit]