1886 Belgian general election
Appearance
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69 of the 138 seats in theChamber of Representatives 70 seats needed for a majority | ||||||||||||||||||||||||||||||||||
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Partial general elections were held inBelgiumon 8 June 1886.[1][2]In the elections for theChamber of Representativesthe result was a victory for theCatholic Party,which won 98 of the 138 seats.[2]
Under the alternating system, elections were only held in four out of the nine provinces:Hainaut,Limburg,LiègeandEast Flanders.
The Catholics continued their gains, after the1884 electionsthat gave them a victory over the Liberals. With the defeat of the Liberals by the Catholics in the eight-memberarrondissement of Ghent,the Catholics now had all "Flemish" seats. Catholics also gained both seats of thearrondissement of Waremmeand two out of seven in thearrondissement of Charleroi.
Results[edit]
Chamber of Representatives[edit]
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Party | Votes | % | Seats | |||||
Won | Total | +/– | ||||||
Liberal Party | 18,965 | 51.33 | 37 | 40 | –12 | |||
Catholic Party | 17,979 | 48.67 | 32 | 98 | +12 | |||
Total | 36,944 | 100.00 | 69 | 138 | 0 | |||
Total votes | 36,944 | – | ||||||
Registered voters/turnout | 57,962 | 63.74 | ||||||
Source: Mackie & Rose,[3]Sternbergeret al. |