1892 United States presidential election in Rhode Island
Appearance
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County Results
Harrison 40-50% 50-60%
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Elections in Rhode Island |
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The1892 United States presidential election in Rhode Islandtook place on November 8, 1892, as part of the1892 United States presidential election.Voters chose four representatives, or electors to theElectoral College,who voted forpresidentandvice president.
Rhode Islandvoted for theRepublicannominee, incumbentPresidentBenjamin Harrison,over theDemocraticnominee, former PresidentGrover Cleveland,who was running for a second, non-consecutive term. Harrison won the state by a narrow margin of 4.96%.
Results[edit]
1892 United States presidential election in Rhode Island[1] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Republican | Benjamin HarrisonofIndiana(incumbent) | Whitelaw ReidofNew York | 26,975 | 50.71% | 4 | 100.00% | ||
Democratic | Grover ClevelandofNew York | Adlai Ewing Stevenson IofIllinois | 24,336 | 45.75% | 0 | 0.00% | ||
Prohibition | John BidwellofCalifornia | James CranfillofTexas | 1,654 | 3.11% | 0 | 0.00% | ||
Populist | James Baird WeaverofIowa | James Gaven FieldofVirginia | 228 | 0.43% | 0 | 0.00% | ||
N/A | Others | Others | 3 | 0.01% | 0 | 0.00% | ||
Total | 53,196 | 100.00% | 4 | 100.00% |
See also[edit]
References[edit]
- ^"1892 Presidential General Election Results - Rhode Island".U.S. Election Atlas.RetrievedDecember 23,2013.