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A098258
Chebyshev polynomials S(n,531) + S(n-1,531) with Diophantine property.
3
1, 532, 282491, 150002189, 79650879868, 42294467207719, 22458282436418921, 11925305679271239332, 6332314857410591666371, 3362447263979344903603669, 1785453164858174733221881868, 948072268092426803995915668239
OFFSET
0,2
COMMENTS
(23*a(n))^2 - 533*b(n)^2 = -4 with b(n)=A098259(n) give all positive solutions of this Pell equation.
FORMULA
a(n) = S(n, 531) + S(n-1, 531) = S(2*n, sqrt(533)), with S(n, x)=U(n, x/2) Chebyshev's polynomials of the second kind,A049310.S(-1, x)= 0 = U(-1, x). S(n, 531)=A098257(n).
a(n)= (-2/23)*i*((-1)^n)*T(2*n+1, 23*i/2) with the imaginary unit i and Chebyshev's polynomials of the first kind. See the T-triangleA053120.
G.f.: (1+x)/(1-531*x+x^2).
a(n) = 531*a(n-1) - a(n-2), n > 1; a(0)=1, a(1)=532. -Philippe Deléham,Nov 18 2008
EXAMPLE
All positive solutions of Pell equation x^2 - 533*y^2 = -4 are (23=23*1,1), (12236=23*532,530), (6497293=23*282491,281429), (3450050347=23*150002189,149438269),...
MATHEMATICA
LinearRecurrence[{531, -1}, {1, 532}, 20] (*Harvey P. Dale,Oct 09 2018 *)
PROG
(GAP) a:=[1, 532];; for n in [3..12] do a[n]:=531*a[n-1]-a[n-2]; od; Print(a); #Muniru A Asiru,Apr 29 2019
KEYWORD
nonn,easy
AUTHOR
Wolfdieter Lang,Sep 10 2004
STATUS
approved