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A000256
Number of simple triangulations of the plane with n nodes.
(Formerly M2923 N1173)
6
1, 1, 0, 1, 3, 12, 52, 241, 1173, 5929, 30880, 164796, 897380, 4970296, 27930828, 158935761, 914325657, 5310702819, 31110146416, 183634501753, 1091371140915, 6526333259312, 39246152584304, 237214507388796, 1440503185260748
OFFSET
3,5
COMMENTS
A triangulation is simple if it contains no separating 3-cycle. The triangulations are rooted with three fixed exterior nodes. -Andrew Howroyd,Feb 24 2021
REFERENCES
N. J. A. Sloane, A Handbook of Integer Sequences, Academic Press, 1973 (includes this sequence).
N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).
W. T. Tutte, The enumerative theory of planar maps, pp. 437-448 of J. N. Srivastava, ed., A Survey of Combinatorial Theory, North-Holland, 1973.
LINKS
Hsien-Kuei Hwang, Mihyun Kang, and Guan-Huei Duh,Asymptotic Expansions for Sub-Critical Lagrangean Forms,LIPIcs Proceedings of Analysis of Algorithms 2018, Vol. 110. Schloss Dagstuhl-Leibniz-Zentrum für Informatik, 2018.
Simon Plouffe,Approximations de séries génératrices et quelques conjectures,Dissertation, Université du Québec à Montréal, 1992; arXiv:0911.4975 [math.NT], 2009.
Simon Plouffe,Une méthode pour obtenir la fonction génératrice d'une série.FPSAC 1993, Florence. Formal Power Series and Algebraic Combinatorics; arXiv:0912.0072 [math.NT], 2009.
P. N. Rathie,A census of simple planar triangulations,J. Combin. Theory, B 16 (1974), 134-138.
William T. Tutte,A census of planar triangulations,Canad. J. Math. 14 (1962), 21-38.
William T. Tutte,A Census of Planar Maps,Canad. J. Math. 15 (1963), 249-271.
FORMULA
a(n) = (1/4)*(7*binomial(3*n-9, n-4)-(8*n^2-43*n+57)*a(n-1)) / (8*n^2-51*n+81), n>4. -Vladeta Jovovic,Aug 19 2004
(1/4 + 7/8*n - 9/8*n^3)*a(n) + (-5/4 + 2/3*n + 59/12*n^2 - 13/3*n^3)*a(n+1) + (-1 - 2/3*n + n^2 + 2/3*n^3)*a(n+2). -Simon Plouffe,Feb 09 2012
a(n) ~ 3^(3*n-6+1/2)/(2^(2*n+3)*sqrt(Pi)*n^(5/2)). -Vaclav Kotesovec,Aug 13 2013
FromGheorghe Coserea,Jul 31 2017: (Start)
G.f. y(x) satisfies (with offset 0):
y(x*g^2) = 2 - 1/g, where g=A000260(x). (eqn 2.6 in Tutte's paper)
0 = x*(x+4)^2*y^3 - x*(6*x^2+51*x+76)*y^2 + (12*x^3+108*x^2+115*x-1)*y - (8*x^3+76*x^2+54*x-1).
0 = x*(27*x-4)*deriv(y,x) + x*(7*x+28)*y^2 - 2*(14*x^2+45*x+1)*y + 2*(14*x^2+34*x+1).
(End)
MAPLE
R:= RootOf(x-t*(t-1)^2, t); ogf:= series( (2*R^3+2*R^2-2*R-1)/((R-1)*(R+1)^2), x=0, 20); #Mark van Hoeij,Nov 08 2011
MATHEMATICA
r = Root[x - t*(t - 1)^2, t, 1]; CoefficientList[ Series[(2*r^3 + 2*r^2 - 2*r - 1)/((r - 1)*(r + 1)^2), {x, 0, 24}], x] (*Jean-François Alcover,Mar 14 2012, after Maple *)
PROG
(PARI)
A000260_ser(N) = {
my(v = vector(N, n, binomial(4*n+2, n+1)/((2*n+1)*(3*n+2))));
Ser(concat(1, v));
};
A000256_seq(N) = {
my(g =A000260_ser(N)); Vec(subst(2 - 1/g, 'x, serreverse(x*g^2)));
};
A000256_seq(24)
\\ test: y = Ser(A000256_seq(200)); 0 == x*(x+4)^2*y^3 - x*(6*x^2+51*x+76)*y^2 + (12*x^3+108*x^2+115*x-1)*y - (8*x^3+76*x^2+54*x-1)
\\Gheorghe Coserea,Jul 31 2017
(PARI) seq(n)={my(g=1+serreverse(x/(1+x)^4 + O(x*x^n) )); Vec(2 - sqrt(serreverse( x*(2-g)^2*g^4)/x ))} \\Andrew Howroyd,Feb 23 2021
CROSSREFS
First row of array inA210664.
KEYWORD
nonn,nice
EXTENSIONS
More terms fromVladeta Jovovic,Aug 19 2004
STATUS
approved