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A228036
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(10^n)-th primitive antiharmonic number.
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3
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OFFSET
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0,2
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COMMENTS
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We conjecture that lim_{n->oo} a(n)/100^n = lim_{n->oo}A228023(n)/n^2 = 6. This is supported by the values a(n)/(10^n)^2 = 6.05, 5.10, 5.84, 5.99, 6.05 for n = 1..5, as well as by the values ofA228023(n)/n^2.
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LINKS
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FORMULA
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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