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A023888
Sum of prime power divisors of n (1 included).
11
1, 3, 4, 7, 6, 6, 8, 15, 13, 8, 12, 10, 14, 10, 9, 31, 18, 15, 20, 12, 11, 14, 24, 18, 31, 16, 40, 14, 30, 11, 32, 63, 15, 20, 13, 19, 38, 22, 17, 20, 42, 13, 44, 18, 18, 26, 48, 34, 57, 33, 21, 20, 54, 42, 17, 22, 23, 32, 60, 15, 62, 34, 20, 127, 19, 17, 68, 24, 27
OFFSET
1,2
COMMENTS
Sum of n-th row of triangleA210208.[Reinhard Zumkeller,Mar 18 2012]
LINKS
FORMULA
a(n) =A000203(n) -A035321(n) =A023889(n) + 1.
a(1) = 1, a(p) = p+1, a(pq) = p+q+1, a(pq...z) = (p+q+...+z) + 1, a(p^k) = (p^(k+1)-1) / (p-1), for p, q = primes, k = natural numbers, pq...z = product of k (k > 2) distinct primes p, q,..., z.
G.f.: x/(1 - x) + Sum_{k>=2} floor(1/ Omega (k))*k*x^k/(1 - x^k), where Omega (k) is the number of distinct prime factors (A001221). -Ilya Gutkovskiy,Jan 04 2017
EXAMPLE
For n = 12, set of such divisors is {1, 2, 3, 4}; a(12) = 1+2+3+4 = 10. From
MAPLE
f:= n -> 1 + add((t[1]^(t[2]+1)-t[1])/(t[1]-1), t=ifactors(n)[2]):
map(f, [$1..100]); #Robert Israel,Jan 04 2017
MATHEMATICA
Array[ Plus @@ (Select[ Divisors[ # ], (Length[ FactorInteger[ # ] ]<=1)& ])&, 70 ]
PROG
(PARI) for(n=1, 100, s=1; fordiv(n, d, if((ispower(d,, &z)&&isprime(z)) || isprime(d), s+=d)); print1(s, "," ))
(Haskell)
a023888 = sum. a210208_row --Reinhard Zumkeller,Mar 18 2012
(PARI)
a(n) = {
my(f = factor(n), fsz = matsize(f)[1]);
1 + sum(k = 1, fsz, f[k, 1]*(f[k, 1]^f[k, 2] - 1)\(f[k, 1]-1));
};
vector(100, n, a(n)) \\Gheorghe Coserea,Jan 04 2017
KEYWORD
nonn
STATUS
approved