Discussion
Fri Jun 28
04:09
J.S. Seneschal:*[A006002(n8)]
04:17
Joerg Arndt:Frankly, this is a waste of time.
05:26
J.S. Seneschal:A little insight into what precisely makes this time wasting may help in preventing further wasting of time in the future...?
Mon Jul 01
20:22
Alois P. Heinz:tivial formulas written in terms of other trivial formulas...
... this one is missing: a(n) = A000290(n+1)*n/2...
21:37
J.S. Seneschal:I see, thank you for the explanation. I was just confused as to why there was no prior reference to A002378 or A027480 here and figured I had to include some sort of formula to justify the addition of a crossref - and seeing that there were already other such trivial formulas here, and that I have had similar trivial formulas approved elsewhere, it would be acceptable. In future I can just add a crossref by itself, then?
FORMULA
a(n) = (A002378(n)^2/2)/normultipliedbythearithmeticmeansofthefirstnpositiveintegers.
Discussion
Fri Jun 28
04:09
J.S. Seneschal:OK, I see what you mean re: (n+1)/2 - but the formula still should work, no? Example for, say, index #8: (8+1)/2 = 4.5; 4.5 * 72 [A002378(n8)] = 324 [A0060029(n8)] - or am I missing something completely obvious?
Discussion
Fri Jun 28
03:35
Michel Marcus:(1+(n-1)/2) was/is (n+1)/2 so I don't see where you are going now
FORMULA
a(n) = (1+A002378(n-1)^2/2)*
Discussion
Thu Jun 27
10:27
Michel Marcus:First part of first formula: (1+(n-1)/2)?
10:57
Michel Marcus:gives 1, 3/2, 2, 5/2, 3, 7/2, 4, 9/2, so not like you say?
21:54
J.S. Seneschal:Seems correct to me: (1+(0/2))*2=2, (1+(1/2))*6=9, (1+(2/2))*12=24... (1+(39/2))*1640=33620, etc.
Fri Jun 28
02:44
Michel Marcus:please simplify (1+(n-1)/2)
02:45
Michel Marcus:21:54 yes, but First part of first formula should produce the series 1,1.5,2,2.5,3,3.5,4,4.5... etc. Not sure if formula is correct or if that series already has an A_id?? is not ok as far I can see
02:46
J.S. Seneschal:As per simplification of A027480 - would a better formula for this be:
A002378(n)^2/2 / n?
FORMULA
a(n) = (1+(n-1)*0.5/2) *A002378(n).
Discussion
Thu Jun 27
07:33
Michel Marcus:*0.5 should be /2
Discussion
Thu Jun 27
06:56
J.S. Seneschal:First part of first formula should produce the series 1,1.5,2,2.5,3,3.5,4,4.5... etc. Not sure if formula is correct or if that series already has an A_id??
